Download Advanced Bash−Scripting Guide by Mendel Cooper PDF

By Mendel Cooper

Данное руководство не предполагает наличие у читателя познаний в области программирования на языке сценариев, однако, быстро восполняет этот недостаток . . . постепенно, шаг за шагом раскрывая мудрость и красоту Unix(tm). Это руководство может рассматриваться как учебник, предназначенный для самостоятельного изучения или как справочник по программированию на shell. Руководство снабжено серией хорошо прокомментированных примеров, поскольку лучший путь к изучению языка сценариев -- это написание сценариев.

Кроме того, эта книга может служить в качестве учебного пособия по основам програмирования вообще.

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Chapter 5. 7" # List of files as argument(s) to a command. # Add two files to the list, and list all. ls −l /usr/X11R6/bin/xsetroot /sbin/dump $file_list echo "−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−" # What happens if we escape a couple of spaces? ls −l /usr/X11R6/bin/xsetroot\ /sbin/dump\ $file_list # Error: the first three files concatenated into a single argument to 'ls −l' # because the two escaped spaces prevent argument (word) splitting. The escape also provides a means of writing a multi−line command.

Positional parameters arguments passed to the script from the command line: $0, $1, $2, $3 . . Chapter 4. Introduction to Variables and Parameters 30 Advanced Bash−Scripting Guide $0 is the name of the script itself, $1 is the first argument, $2 the second, $3 the third, and so forth. [16] After $9, the arguments must be enclosed in brackets, for example, ${10}, ${11}, ${12}. The special variables $* and $@ denote all the positional parameters. Example 4−5. " # Strips out path name info (see 'basename') echo if [ −n "$1" ] then echo "Parameter #1 is $1" fi # Tested variable is quoted.

Integer or string? sh: Integer or string? a=2334 let "a += 1" echo "a = $a " echo # Integer. b=${a/23/BB} # # # # # echo "b = $b" declare −i b echo "b = $b" let "b += 1" echo "b = $b" echo c=BB34 echo "c = $c" d=${c/BB/23} echo "d = $d" let "d += 1" echo "d = $d" echo # a = 2335 # Integer, still. Substitute "BB" for "23". This transforms $b into a string. b = BB35 Declaring it an integer doesn't help. b = BB35 # BB35 + 1 = # b = 1 # # # # # # c = BB34 Substitute "23" for "BB". This makes $d an integer.

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